monserrat0179 monserrat0179
  • 19-01-2021
  • Mathematics
contestada

Evaluate. Type "no real solution" if no real solutions exist.
f() = (x+2)^2 – 3
f(3)=
f(-2)=
f(0)=
f(-4) =

Respuesta :

iahorrtaes
iahorrtaes iahorrtaes
  • 20-01-2021

Answer: If there is no real solution, enter NO REAL SOLUTION.)  Find all solutions of the equation and express them in the form  x^3 − 2x^2 − 7x + 14 = 0. -separate the problem into factoring: x^3 and 2x^2 will be the outside numbers √(x + 42)=x ... Use f(x) = 4x − 3 and g(x) = 5 − x^2 to evaluate the expression. (f o g) (-2)

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