Answer:
44.8L of hydrogen gas
Explanation:
The reaction expression is given as:
      2Na  +  2H₂O  →   2NaOH   +  H₂
Given parameters:
Mass of sodium  = 92.4g
Unknown:
Volume of hydrogen gas  =  ?
Solution:
To solve this problem:
      1 mole of a substance at STP occupies a volume of  22.4L
Let us find the number of moles of the hydrogen gas;
 Number of moles of Na = [tex]\frac{mass}{molar mass}[/tex] Â
   Molar mass of Na = 23g/mol
 Number of moles  = [tex]\frac{92.4}{23}[/tex]   = 4.02mole
From the balanced reaction expression:
    2 mole of Na will produce 1 mole of hydrogen gas
   4.02 mole of Na will produce [tex]\frac{4.02}{2}[/tex]  = 2mole of hydrogen gas
So
     1 mole of a substance at STP occupies a volume of  22.4L
    2 mole of hydrogen gas will occupy a volume of 2 x 22.4  = 44.8L of hydrogen gas
