Fernando293187 Fernando293187
  • 21-01-2021
  • Chemistry
contestada

.A gas occupies 25,3 mL at a pressure of 152 kPa. Find the volume if the pressure is
reduced to 0.804 atm.
10

Respuesta :

samueladesida43
samueladesida43 samueladesida43
  • 26-01-2021

Answer:

47.36mL

Explanation:

Using Boyles law equation, which states that:

P1V1 = P2V2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

P1 = initial pressure (atm)

P2 = final pressure (atm)

Based on the provided information, V1 = 25.3mL, P1 = 152 kPa, V2 = ?, P2 = 0.804atm

First, we need to convert 152kPa to atm by dividing by 101

1kPa = 0.0099atm

152kPa = 1.505atm

P1V1 = P2V2

1.505 × 25.3 = 0.804 × V2

38.08 = 0.804V2

V2 = 38.08/0.804

V2 = 47.36mL

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