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2) The area of a rectangular pool is 1260 ft. Find the dimensions of the rectangle, if one
side of the pool is 48 ft more than three times the other side?

Respuesta :

Two equations

W*L=1260

3W+48=L

Solve

L=1260/W

3W+48=1260/W

3W^2+48W=1260

3W^2+48W-1260=0

Divide by 3

W^2+16W-420=0

Factor

(W-14) (W+30)

W=14

L=90





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