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The pressure on 200 mL of a gas is reduced from 80 kPa to 40 kPa. The final volume is Page
A)400 mL
B)40 mL
C)16 mL
D)100 mL

Respuesta :

abidemiokin

Answer:

400mL

Explanation:

According to Boyle's law;

PV= k

P1V1 = P2V2

P are the pressures

V are the volumes

V1 = 200mL

P1 = 80kPa

P2 = 40kPa

Required

V2

V2 = P1V1/P2

V2 = 80*200/40

V2 = 2 * 200

V2 = 400mL

Hence the final volume is 400mL

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