Answer:
2 M
Explanation:
NaOH + HCl --> NaCl + H2O,
5.54 mL = .00545 L,
If we consider 2.18 M, M [molarity] = mol/L, so we have 2.18 mol/L. From this we can get the moles of NaOH.
.00545 L * 2.18 mol/L ≈ .0121 mol
The concentration of HCl can be found from the following:
.0121 mol = .00619(x) [where x = concentration of HCl]
x = 1.955 M ≈ 2 M
We equate the two as we require the same amount in order to neutralize the base.
