meredith48034
contestada

1. Find the value of
sec Θ if tan Θ = -2 90° ≤ Θ ≤ 180°

a. - sqrt(5)
b. sqrt(5)
c. -5
d. 5

2. Find the value of cos Θ if sec Θ = s/3 270° ≤ Θ ≤ 360°

cos =

3. Find the value of
csc Θ of cos Θ = -3/5 180° ≤ Θ ≤ 270°
csc =

Respuesta :

sqdancefan

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Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

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