hamadmaad hamadmaad
  • 19-03-2021
  • Physics
contestada

A 65.0 kg skier slides down a 37.20 slope with mu = 0.107.

What is the friction force?

Respuesta :

trainboxcar20 trainboxcar20
  • 19-03-2021

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N

Answer Link
madey21
madey21 madey21
  • 11-07-2022

Answer:

magnitude of friction force- 54.3

friction force- -54.2

Explanation:

Answer Link

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