points of discontinuity.
y = cot x, [0, 2 \[\pi \] ]

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19-11-2016
Mathematics

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points of discontinuity.
y = cot x, [0, 2 \[\pi \] ]

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syed514 syed514 · Answer 1 · 2016-11-20T18:42:43+01:00

syed514 syed514

20-11-2016

cotx = (cosx)/(sinx)
Where is this function not defined?
i.e. where is sin(x)=0?
Because at this point, cotx will be undefined because you cannot divide by zero. So find all points from 0 to 2 pi where sinx is 0.

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points of discontinuity. y = cot x, [0, 2 \[\pi \] ]

Respuesta :

Otras preguntas

points of discontinuity.
y = cot x, [0, 2 \[\pi \] ]