Answer:
[tex]x \ge -2[/tex] or [tex]x < -5[/tex]
Step-by-step explanation:
Given
[tex]5+x\ge3[/tex] or [tex]6x+1<-29[/tex]
Required
The solution
[tex]5+x\ge3[/tex]
Solve for x
[tex]x \ge 3 - 5[/tex]
[tex]x \ge -2[/tex]
[tex]6x+1<-29[/tex]
Solve for 6x
[tex]6x < -29 - 1[/tex]
[tex]6x < -30[/tex]
Solve for x
[tex]x < -30/6[/tex]
[tex]x < -5[/tex]
Hence, the solution is:
[tex]x \ge -2[/tex] or [tex]x < -5[/tex]
