9514 1404 393
Answer:
$4047
Step-by-step explanation:
For an interest rate r compounded n times per year for t years, the effective multiplier is ...
(1 +r/n)^(nt)
The multiplier for the first 5 years is ...
(1 +0.07/2)^(2·5) = 1.41059876
The multiplier for the last 5 years is ...
(1 +0.0728/4)^(4·5) = 1.43437218
Then the account value at the end of 10 years is ...
$2000(1.41059876)(1.43437218) ≈ $4047 . . . . balance after 10 years
