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16-05-2021
Chemistry

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What is the pOH of a 0.013 M Ca(OH)2 solution?

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chayalalowy chayalalowy

16-05-2021

Answer:1.59

Explanation: For every mol of Ca(OH)2 there are two moles of OH so the concentration of OH is .013 x2 =.026 M OH

pOH = - log [OH] so -log .026 = 1.59

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