Answer:
[tex]V_2=5.32L[/tex]
Explanation:
Hello there!
In this case, according to the given pressure, temperature and volume, it is possible for us to calculate the final volume via the combined ideal gas law:
[tex]\frac{P_2V_2}{T_2}=\frac{P_1V_1}{T_1}[/tex]
In such a way, we solve for the final volume, V2, to obtain:
[tex]V_2=\frac{P_1V_1T_2}{T_1P_2}[/tex]
Then, we plug in the given data to obtain:
[tex]V_2=\frac{1.19atm*2.3L*380K}{326K*0.60atm}\\\\V_2=5.32L[/tex]
Regards!
