marianagalvan683 marianagalvan683

18-05-2021
Mathematics

contestada

5. Find the Area (A = L x W) of a square that has a length measuring 3a²b²c1

Respuesta :

abidemiokin abidemiokin

23-05-2021

Answer:

9a^4b^4c^2

Step-by-step explanation:

Area of a square is expressed using the formula

A =L²

L is the side length of the square

Given that;

L = a²b²c

A = 3²(a²b²c)²

A = 9(a²)²(b²)²c²

A = 9a^4b^4c^2

Hence the area of the square is 9a^4b^4c^2

Answer Link

Otras preguntas

why aren't citizens interested in local politics

Which of the following best expresses the law of diminishing returns? Proportionate increases in the inputs of all resources will result in a less-than-proporti

slove: 3/2 (x-6) = -3

1st question: Are the angles adjacent or vertical? 2nd question: Find the value for x.m

If f(x) = x + 1, and g(x) = 2x, then f(g(x)) = [ ? ]x + [ ]

is 6.7 and 6.40 equal?

If x≠-4, which answer choice represents the following in simplified form (question attached) A. X+3 B. X-4 C. 2x+6 D. X-3

Can y’all help me please

The number 312.8 is 34% of x. What is the value of x rounded to the nearest whole number

True or false: Support for the Palestinian Liberation Organization increased as the number of Palestinian refugees also increased