Respuesta :

sreedevi102

Answer:

[tex]Hypotenuse^2 = 5^2 + 2^2 = 25 + 4 = 29\\\\Hypotenuse= \sqrt{29}\\\\diagonal^2 = (\sqrt{29})^2 + 2^2\\\\diagonal^2 = 29 + 4 = 33\\\\diagonal = \sqrt{33} = 5.7445 = 5.8[/tex]