Respuesta :

unicorn3125

Answer:

            y = (x - 2)² - 3

            y = 0  if  x = 2+√3  or   2-√3

Step-by-step explanation:

[tex]y = x^2 - 4x + 1\\\\y = \underline{x^2 - 2\cdot x\cdot2+2^2}-2^2 +1\\\\y=(x-2)^2-4+1 \\\\y=(x-2)^2-3\\\\\\y=0\quad\iff\quad(x-2)^2-3=0\\\\(x-2)^2=3\\\\x-2=\pm\sqrt3\\\\x=2\pm\sqrt3[/tex]

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