Respuesta :

msm555

Answer:

Solution given:

m∠ADB=(4x−12)°

m∠CDB=(3x+6)°

m∠ADC =?

Since diagonal BD bisect the angle <ADC

so

m∠ADB= m∠ADC

(4x-12)°=(3x+6)°

4x-3x=6-12

x=12+6

x=18°

again.

<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°

So

the m∠ADC =120°

Ver imagen msm555

As it's a rhoumbus angles are equal

  • m<ADB=m<CDB
  • 4x-12=3x+6
  • x=18

m<ADC

  • 4x-12+3x+6
  • 7x-6
  • 7(18)-6
  • 126-6
  • 120°
Ver imagen Аноним