kiryahlee67
kiryahlee67 kiryahlee67
  • 16-07-2021
  • Mathematics
contestada

ANSWER ASAP ILL MARK BRAINLIEST!!!!
find all the real zeros of the quadratic function.
f(x)=2x²-6x-1​

Respuesta :

EMEGroup
EMEGroup EMEGroup
  • 16-07-2021

Answer:

[tex]2 {x}^{2} - 6x - 1 = 0 \\ a = 2 \: \: \: b = - 6 \: \: \: c = - 1 \\ \\ x = \frac{6\binom{ + }{ - } \ \sqrt{ {6}^{2} - 4(2)( - 1)} }{2 \times 2} \\ \\ x = \frac{6 \binom{ + }{ - } \sqrt{44} }{4} \\ x = \frac{6 + \sqrt{44} }{4} \\ \\ or x = \frac{6 - \sqrt{44} }{4} [/tex]

I hope that is useful for you :)

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