9514 1404 393
Answer:
3
Step-by-step explanation:
20 has at most 3 proper factors greater than 1: 2×2×5. Each of these can represent a prime factor of the number of interest, and is 1 more than that prime's power. That is, the number of interest (n) will have at most 3 prime factors p, q, r, and will be ...
n = p·q·r^4
_____
For some prime factorization ...
[tex]\displaystyle n=\prod_{k=1}^m{p_k^{q_k}}[/tex]
The total number of divisors of n is ...
[tex]\displaystyle\prod_{k=1}^m{(q_k+1)}[/tex]
