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18-09-2021
Physics

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A train is moving at 15ms-1. It slows down to 10.5ms over a time of 4s. Calculate the distance it travels before stopping if acceleration is constant.

Respuesta :

18-09-2021

Answer:

(v2 - v1) / t = a for uniform acceleration

a = (10.5 - 15) / 4 = -1.125 m / s^2

T = 15 / 1.125 = 13.3 s time for train to stop from 15 m/s

S = V0 T + 1/2 a T^2

S = 15 * 13.3 - 1.125 / 2 * 13.3^2

S = 199.5 - 99.5 = 100 m

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