Step-by-step explanation:
Logx + Log(x+3)=2log(x+1)
Log x(x+3) = Log (x+1)²
x(x+3)=(x+1)²
x²+3x = x²+2x+1
delete x², we find
3x = 2x+1
3x-2x = 1
x = 1
