tolsonem6
tolsonem6 tolsonem6
  • 16-10-2021
  • Mathematics
contestada

PLEASE ANSWER FAST!
Find BDC.
BDC=​

PLEASE ANSWER FASTFind BDC BDC class=

Respuesta :

prasamsharayamajhi
prasamsharayamajhi prasamsharayamajhi
  • 16-10-2021

Answer:

angle BDC= 95°............

Answer Link
priyodiptobasak
priyodiptobasak priyodiptobasak
  • 16-10-2021

Step-by-step explanation:

<NDC=<NCD (Given)

<NCD=35°.

<CAN=<DBN (Given)

<DBN=50°.

therefore, <CND = 180-35-35=110.

and <CND and <DNB are linear pair.

<CND+<DNB=180°

<DNB=180-110

<DNB=70.

therefore, <BDN = 180-50-70 = 60.

therefore, <BDC= 35°+60°=95°.

hope this helps you.

Answer Link

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