stephanieuwu24
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- Please help ASAP and include steps (pls no links)
Which of the following would contain the largest number of atoms?
1. 1.00 gram of beryllium (Be)
2. 1.00 gram of uranium (U)
3. 1.00 gram of sulfur (S)
4. 1.00 gram of iron (Fe)
5. All contain the same number of atoms

Respuesta :

Answer:

2. 1 gram of Uranium (U)

Explanation:

1.

1 g Be x 1 mol/ 9.012182 g = 0.1109609193 mol Be

0.1109609193 mol Be x 6.0221409e+23/ 1 mol = 6.68x10^22 atoms of Be

2.

1 g U x 1 mol/ 238.0289 g = 4.20117053x10^-03 mol U

4.20117053x10^-03 mol U x 6.0221409e+23/ 1 mol = 2.53x10^21

3.

1 g S x 1 mol/ 32.066 g = 0.03118567954 mol S

0.03118567954 mol S x 6.0221409e+23/ 1 mol = 1.88x10^22

4.

1 g Fe x 1 mol/ 55.847 g = 0.01790606478 mol Fe

0.01790606478 mol Fe x 6.0221409e+23/ 1 mol = 1.078328451x10^22

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