Respuesta :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's solve :

  • [tex](b + 1)3 - (b - 1)[/tex]

  • [tex]3b + 3 - b + 1[/tex]

  • [tex]2b + 4[/tex]

Answer:

Step-by-step explanation:

i think he is asking

(b+1)³-(b-1)

=b³+1³+3b*1(b+1)-b+1

=b³+1+3b²+3b-b+1

=b³+3b²+2b+2

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