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a typical 100-watt light bulb consumes 100 j of energy per second. if a light bulb converts all of this energy to 400 nm light, how many photons are produced each second?

Respuesta :

Answer:

Let y equal lambda the wavelength of the light

e (photon) = h f = h c / y

e = 6.63E-34 * 3.0E8 / 400E-9

e = 6.63 * 3  / 400 * 10^-17

e = 4.97E-19

N= 100 J/sec/ 4.97E-19 J = 2.01E20 / sec

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