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If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amperes·meter at a speed of 4.20 meters/second, what is the length of the wire in the magnetic field? A. 0.27 meters B. 2.8 meters C. 0.020 meters D. 3.7 meters

Respuesta :

aidanlsachs
We know that EMF = L B v

Subbing in, we see that 0.88 = L (0.075) (4.2) => L = 0.88 / (0.075*4.2) = 2.794, which rounds to 2.8 m

Therefore, the correct answer is B

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