Respuesta :

fichoh

Using the normal distribution principle, the Zscore associated with a probability value of 54.55% is 0.114

Given the Probability value :

  • P(z < Z) = 54.55%

Using a normal distribution table or calculator :

P( z < Zscore ) = 0.5455

Zscore = 0.114

Therefore, the Zscore associated with a probability value id 54.55% is 0.114

Learn more :https://brainly.com/question/25641959