astrotales4163 astrotales4163
  • 19-11-2021
  • Mathematics
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M*(x+y)+4y/(x^2-xy-y^2)=(x+2y)/(x^2-xy-Y^2),find the value of M

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xiaoline4ever
xiaoline4ever xiaoline4ever
  • 19-11-2021

Answer: M  = [tex]\frac{x-2y}{x+y}[/tex]  

Step-by-step explanation:

[tex]\frac{M(x+y)+4y}{x^{2}-xy-y^{2} } =\frac{(x+2y)}{x^{2} -xy-y^{2} }[/tex]

M (x + y) + 4y = x + 2y (Multiply [tex]x^{2} - xy-y^{2}[/tex] in both sides)

M (x + y)  = x + 2y - 4y

M (x + y)  = x - 2y  (Divide (x+y) from both sides)

M  = [tex]\frac{x-2y}{x+y}[/tex]  

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