Respuesta :

hnori22003

[tex] \frac{35 - 3}{20 - 4} = \\ [/tex]

[tex] \frac{32}{16} = \\ [/tex]

[tex]2[/tex]

d = 2

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t(4) = t(1) + 3d

3 = t(1) + 3×2

3 = t(1) + 6

t(1) = 3 - 6

t(1) = - 3

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t(n) = t(1) + (n-1)(d)

t(32) = - 3 + 31×2

t(32) = -3 + 62

t(32) = 59

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