Respuesta :

DivyaLOL

Answer:

18

At STP, 22.4 liters of a gas forms one mole that is 6.023×10

23

molecules.

Volume of CO

2

in 1 litre of air =

100

0.03

×1 L

∴ No. of molecules of CO

2

=

22.4

6.023×10

23

×

100

0.03

=8.066×10

18

Explanation:

I guess it's this

  • R=8.314J/molK
  • P=772mmHg
  • T=0°C=273K
  • V=20L

[tex]\\ \sf\longmapsto PV=nRT[/tex]

[tex]\\ \sf\longmapsto n=\dfrac{PV}{RT}[/tex]

[tex]\\ \sf\longmapsto n=\dfrac{772(20)}{8.314(273)}[/tex]

[tex]\\ \sf\longmapsto n=\dfrac{15440}{2269.722}[/tex]

[tex]\\ \sf\longmapsto n=6.8mol[/tex]

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