madisonpierce75084 madisonpierce75084

17-01-2022
Mathematics

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for the problem 1/5g - 1/10 -g+ 1/3/10g -1/10 tyson created an equivalent expression using the folling steps is his final expression equivalent to the initial expression

for the problem 15g 110 g 1310g 110 tyson created an equivalent expression using the folling steps is his final expression equivalent to the initial expression class=

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adioabiola adioabiola

21-01-2022

No, Tyson's final expression is not equivalent to the initial expression.

Fraction addition;

According to Tyson's evaluation after collecting like terms; we have;

1/5g +(-1g) + 1(3/10g) + (-1/10) + (-1/10)

open parenthesis

1/5g - 1g + 3/10g - 1/10 - 1/10

Upon addition of like terms; we have;

(-1/2)g -1/5.

Hence, the correct expression is; (-1/2)g -1/5

Read more on fraction addition;

https://brainly.com/question/11562149

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