Ciscohernandez0702 Ciscohernandez0702

20-01-2022
Mathematics

contestada

The tv shown below has a diagonal of 19 cm and a width of 9
cm. To the nearest centimeter, what is the length of the
rectangle?

Respuesta :

ranismita222 ranismita222

20-01-2022

Using the formula

d=w^2+l^2

Solving for l

l=√d^2﹣w^2 = √19^2﹣9^2

≈16.7332cm

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