brazzydoll1234
brazzydoll1234 brazzydoll1234
  • 19-02-2022
  • Mathematics
contestada

In how many ways can first, second, and third prizes be awarded in a contest with 600 contestants?

Respuesta :

chibabykalu16
chibabykalu16 chibabykalu16
  • 19-02-2022

Answer:

214,921,200 ways

Step-by-step explanation:

[tex]first \: price \: to \: one \: of \: the \: 600 \: \\ participant \\ so \: 600 \: choices \\ 2nd \: 599 \: choices \\ 3rd \: 598 \: choices \\ simplify \: 600 \times 599 \times 598 = \\ = 214,921,200[/tex]

Answer Link
Lenvy
Lenvy Lenvy
  • 25-03-2022

Answer:

214,921,200 ways

Step-by-step explanation:

First = 600

Second = 599

Third = 598

Hence,

600 × 599 × 598

359400 × 598

214,921,200

Hence, in 214,921,200 different ways.

~Lenvy~

Answer Link

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