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A body of mass 10 kg is being rotated in a circular path of
diameter 1.0 mm on a frictionless horizontal plane by means of
a string. It performs 10 revolutions in 3.14 s. Calculate the
centripetal force acting on it.​

Respuesta :

TheUnknownScientist

Answer:

The answer is 2N

Explanation:

Given;

  • mass (m) = 10 kg
  • Diameter (d) = 1 mm

To Find;

  • The centripetal force acting on it.

Now,

Radius (r) = Diameter ÷ 2

r = 1/2

r = 0.5 mm = 5 × 10‾⁴

T = 3.14 ÷ 10 = π/10 sec

∴ F = mrω² = mr (2π/T)² = 4π²mr/T²

F = 4 π² × 10 × 5 × 10‾⁴/(π/10)²

F = 4 π² × 10 × 5 × 10‾⁴ × 100/π²

F = 4 × 0.5

F = 2 N

Thus, The centripetal force acting on it is 2 Newton

 

-TheUnknownScientist 72

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