arnoldobecerravazque arnoldobecerravazque
  • 16-05-2022
  • Chemistry
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What is the concentration (molarity) of a solution created by dissolving 81.1 grams of Mg3P2 to create a 2.5 solution?

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  • 16-05-2022

Answer:

The concentration of Mg3P2 solution = 0.24mol/L

Explanation:

Mass = 81.1g

Volume = 2.5L

Concentration (C) of a solution = [tex]\frac{Moles (n)}{Volume (V)}[/tex]

but moles = [tex]\frac{mass}{Molar mass}[/tex]       and      Molar mass of Mg3P2 = 134.88g/mol

Moles = [tex]\frac{81.1g}{134.88g/mol}[/tex]

          = 0.60mol

hence the concentration can be calculated by;

C =  [tex]\frac{0.60mol}{2.5L} \\[/tex]

  = 0.24mol/L or 0.24M

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