25tanben 25tanben
  • 16-05-2022
  • Mathematics
contestada

Evaluate h(x)=-2x+9 when x=-2,0, and 5 .


h(-2)=


h(0)=


h (5)=

Respuesta :

TheUnknownScientist
TheUnknownScientist TheUnknownScientist
  • 16-05-2022

Answer:

The answer is 13, 9 and (-1)

Step-by-step explanation:

Given;

  • h(x) = (-2x + 9)

To Find;

  • h(x) = (-2x + 9) when x = (-2), 0 and 5.

For x = (-2)

h(x) = (-2x + 9)

h(-2) = [-2(-2) + 9]

h(-2) = (4 + 9)

h(-2) = 13

For x = 0

h(x) = (-2x + 9)

h(0) = [-2(0) + 9]

h(0) = (0 + 9)

h(0) = 9

For x = 5

h(x) = (-2x + 9)

h(5) = [-2(5) + 9]

h(5) = [(-10) + 9]

h(5) = (-1)

Thus, The answer is 13, 9 and (-1) when x = (-2), 0 and 5 respectively.

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