jaelyn0514
contestada

What is the equation of a sine function with an amplitude of 2 and a period of 4π?

y = one-half sine (2 x)
y = one-half sine (4 pi x)
y = 2 sine (one-half x)
y = 2 sine (4 pi x)

Respuesta :

The general equation

  • y=Asin(Bx)

B is period and A is amplitude

  • A=2

RearrAnge

  • y=2sinBx

Period:-

  • 2π/4π
  • 2/4
  • 1/2

So final equation

  • y=2sin(1/2x)

Option C

tomchen882

Answer:

c

Step-by-step explanation:

edge

Otras preguntas