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In a family, there are four children. Adam's age is the sum of Beth's and Carol's. Four years ago, David's age was the sum of Beth's age then and Carol's age then. Eight years ago, Adam's age was twice David's age then. Who is the oldest child in this famiy?

Respuesta :

The oldest child in the given family described is; Adam

How to solve algebra word problems?

We are told that;

Adam's age = Beth's age + Carol's age

David's age = Beth's age + Carol's age (4 years ago)

Adam's age = 2 * David's age (8 years ago)

Thus, we can say that Beth and Carol are younger than both Adam and David since Adam's age was twice that of David's age 8 years ago and as such Adam must be the oldest child.

Read more about Algebra problems at; https://brainly.com/question/4344214

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