eyeless937 eyeless937
  • 16-07-2022
  • Mathematics
contestada

If B=3n-10B=3n−10 and C=n^{2}-6n-6,C=n
2
−6n−6, find an expression that equals 2B-3C2B−3C in standard form.

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 18-07-2022

The expression of 2B - 3C in standard form is -3n^2 + 24n - 2

Functions and values

Given the following expressions

B = 3n - 10

C = n^2-6n-6

Required

2B - 3C

Substitute

2B - 3C = 2(3n -10) - 3(n^2-6n-6)

2B - 3C = 6n - 20 -3n^2+18n+18

2B - 3C = -3n^2 + 24n - 2

Hence expression of 2B - 3C in standard form is -3n^2 + 24n - 2

Learn more on expression here; https://brainly.com/question/723406

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