jondoe12121224 jondoe12121224

18-08-2022
Mathematics

contestada

Solve the following system of equations:

x = 40 + 3y
6x + 13y = 550

(5, 55)
(10, 70)
(70, 10)
(100, 20)

Respuesta :

esenter1 esenter1

18-08-2022

(10, 70)

Change the top equation to x-3y=40. Then multiply each value in that equation by 6 to make it 6x-18y=240. Then subtract each value. You should be left with -31y = -310, making y=10.

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