Respuesta :
Answer:
x = - 8
Step-by-step explanation:
calculate the slope of the line containing the 2 points using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (3, 2 ) and (x₂, y₂ ) = (- 7, 2 )
m = [tex]\frac{2-2}{-7-3}[/tex] = [tex]\frac{0}{-10}[/tex] = 0
a line with a slope of zero is a horizontal line parallel to the x- axis
then a perpendicular line will be a vertical line with equation
x = c ( c is the value of the x- coordinates the line passes through )
the line passes through (- 8, 12 ) with x- coordinate - 8 , then
x = - 8 ← equation of perpendicular line
Answer:
x + 8 = 0
Step-by-step explanation:
Solution:
For Slope of st.line with points (3,2) and (-7,2)
Slope(m1) =
= [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
= [tex]\frac{2-2}{-7-3}[/tex]
= 0
Let slope of the required line by m2
Since the lines are perpendicular to each other
m1*m2= -1
0 * m2 = -1
m2 = -1/0
Now,
Passing point = ( -8,12 )
Using single point form, we get:
[tex]y-y_{1} = m_{2}(x-x_{1})\\or, y-12=\frac{-1}{0}(x +8)\\ or, Cross multiplying\\or, 0=-x-8\\or, x+8=0[/tex]
which is the required equation.
If my answer is wrong You can say it I will try to figure it down
