fofafofafo fofafofafo

16-09-2022
Mathematics

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In the figure, m∠AOD=105. If m∠AOB=8x, m∠BOC=7x and m∠COD=6x, what is the value of x?

In the figure mAOD105 If mAOB8x mBOC7x and mCOD6x what is the value of x class=

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jimrgrant1 jimrgrant1

16-09-2022

Answer:

x = 5

Step-by-step explanation:

from the diagram

∠ AOB + ∠ BOC + ∠ COD = ∠ AOD ( substitute values )

8x + 7x + 6x = 105

21x = 105 ( divide both sides by 21 )

x = 5

Answer Link

sogolkermanian3131 sogolkermanian3131

16-09-2022

Answer:

5

Step-by-step explanation:

AOB+BOC+COD=AOD

6x+8x+7x=105

21x=105

x=105÷21

x=5

Answer Link

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