itgetsbetter92 itgetsbetter92
  • 16-09-2022
  • Mathematics
contestada

Two consecutive positive integers such that the square of the second integer added to 4 times the first is equal to 41

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paytonlowery01 paytonlowery01
  • 16-09-2022

Answer:

4 and 5

Step-by-step explanation:

We need 2 positive numbers that are right beside each other, like 1 and 2. When the problem is translates into number format we get:

y^2+4x=41

x = 1st # and y = 2nd #

so if we do 4 (x) and 5 (y)

5^2+4(4)=41

the statement is true.

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