zakaribell zakaribell

18-09-2022
Mathematics

contestada

Someone help meee!

Solve 4(x-3)-2(x-1)>0

Someone help meee Solve 4x32x1gt0 class=

Respuesta :

tgundapaneni21 tgundapaneni21

18-09-2022

Answer:

x>5

Step-by-step explanation:

1. Distribute.

4(x-3)-2(x-1)>0

4x-12-2(x-1)>0

2. Distrubute furthermore

4x-12-2(x-1)>0

4x-12-2x+2>0

3. Add the numbers

4x-12-2x+2>0

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