ShotoXTodoroki
ShotoXTodoroki ShotoXTodoroki
  • 21-09-2022
  • Mathematics
contestada

HELP PLEASE PLEASE 100 POINTS

HELP PLEASE PLEASE 100 POINTS class=

Respuesta :

kandrewel
kandrewel kandrewel
  • 21-09-2022

Answer:

x=29

z=13

<RIG= 59°

<ZIM=31°

step-by-step explanation:

(vertically opposite angles)

<ZIA=<MIG

3x-56=x+2

group like terms

3x-x=56+2

2x=58

divide both side by the coefficient of x

2x/2=58/2

x=29

<RIG+<GIM=90°

4z+7+x+2=90°

where x=29

4z+7+29+2=90°

4z+38=90°

make for 4z the subject

4z=90°-38°

4z=52°

let z stand alone

4z/4=52/4

z=13

<RIG=4z+7

where z=13

4(13)+7

52°=RIGZ

<ZIM=x+2

where x =39+2

x=31°

Answer Link

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