danielnguyen138
danielnguyen138 danielnguyen138
  • 17-02-2017
  • Mathematics
contestada

Suppose g(x)=ax+b, where a and b are real constants. Find all possible pairs (a,b) such that we have g(g(x))=9x+28.
Show work or explain.

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LammettHash
LammettHash LammettHash
  • 17-02-2017
[tex]g(x)=ax+b\implies g(g(x))=g(ax+b)=a(ax+b)+b=a^2x+ab+b[/tex]

You have [tex]a^2=9\implies a=\pm3[/tex], and [tex]ab+b=28[/tex]. If [tex]a=3[/tex], then [tex]3b+b=4b=28\implies b=7[/tex]. If [tex]a=-3[/tex], then [tex]-3b+b=-2b=28\implies b=-14[/tex].

So the possible pairs are [tex](3,7)[/tex] and [tex](-3,-14)[/tex].
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