emilybb195
emilybb195
17-03-2017
Mathematics
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Аноним
Аноним
18-03-2017
[tex]\dfrac{x}{x-5} ~ \cdot~ \dfrac{2x}{x+4} =\dfrac{x~ \cdot~ 2x}{(x-5)(x+4)}= \dfrac{2x^2}{x^2 -x -20}[/tex]
The answer is D.
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