elifleblebici98 elifleblebici98
  • 19-03-2017
  • Physics
contestada

Determine the direction of the effective value of g⃗ at a latitude of 45 ∘ North on the Earth.

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Hagrid
Hagrid Hagrid
  • 02-04-2017
To solve this, we simply use trigonometry
the effective value of g along the 45° angle is
g eff = g / sin 45
g eff = g / (√2 / 2)
g eff = 2g / √2
g eff = g √2 ≈ 6.94 m/s²
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