Respuesta :

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[tex]\dfrac14+\dfrac2{4^2}+\dfrac1{4^3}+\dfrac2{4^4}+\cdots[/tex]
[tex]=\left(\dfrac14+\dfrac1{4^2}+\dfrac1{4^3}+\dfrac1{4^4}+\cdots\right)+\left(\dfrac1{4^2}+\dfrac1{4^4}+\cdots\right)[/tex]
[tex]=\displaystyle\sum_{n=1}^\infty\left(\frac14\right)^n+\sum_{n=1}^\infty\left(\frac14\right)^{2n}[/tex]
[tex]=\displaystyle\sum_{n=0}^\infty\left(\frac14\right)^n-1+\sum_{n=0}^\infty\left(\frac14\right)^{2n}-1[/tex]
[tex]=\displaystyle\sum_{n=0}^\infty\left(\frac14\right)^n+\sum_{n=0}^\infty\left(\frac1{16}\right)^n-2[/tex]
[tex]=\dfrac1{1-\frac14}+\dfrac1{1-\frac1{16}}-2[/tex]
[tex]=\dfrac25[/tex]

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