the hyperbola is more or less as in the picture below
notice the traverse axis is horizontal, meaning the positive fraction will be the one with the "x" variable in it, and notice the length of the "a" component
the conjugate axis is 10, notice the length of the "b" component
thus [tex]\bf \textit{hyperbola with horizontal traverse axis }\\\\
\cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
vertices\ ({{ h}}\pm a, {{ k}})[/tex]
so, hmmmm plug in those values
